CLASS 6 CHAPTER 9: DATA HANDLING

Exercise 9.1

1. In a Mathematics test, the following marks were obtained by 40 students. Arrange

these marks in a table using tally marks.

(a) Find how many students obtained marks equal to or more than 7.

(b) How many students obtained marks below 4?

Solution

The fifth mark in a group of five marks should be used as a cross, as shown by ‘||||’. These are tally marks. Thus, |||| || shows the count to be five plus two (i.e. seven) and |||| |||| shows five plus five (i.e. ten).

The table using tally marks is as follows:

a) There are 5 students who obtained 7, 4 students who obtained 8 and 3 who obtained 9. So, there are 5 + 4 + 3 = 12 students who obtained marks equal to or more than 7.

b) There are 2 students who obtained 1 mark, 3 obtained 2 marks and 3 obtained 3 marks. So, there are 2 + 3 + 3 = 8 students who obtained marks below 4.

2. Following is the choice of sweets of 30 students of Class VI.

Ladoo, Barfi, Ladoo, Jalebi, Ladoo, Rasgulla, Jalebi, Ladoo, Barfi, Rasgulla, Ladoo,

Jalebi, Jalebi, Rasgulla, Ladoo, Rasgulla, Jalebi, Ladoo, Rasgulla, Ladoo, Ladoo,

Barfi, Rasgulla, Rasgulla, Jalebi, Rasgulla, Ladoo, Rasgulla, Jalebi, Ladoo.

(a) Arrange the names of sweets in a table using tally marks.

(b) Which sweet is preferred by most of the students?

Solution

a)

b) Ladoo is preferred by most of the students as the table shows the maximum number for ladoos.

3. Catherine threw a dice 40 times and noted the number appearing each time as shown below:

1 3 5 6 6 3 5 4 1 6

2 5 3 4 6 1 5 5 6 1

1 2 2 3 5 2 4 5 5 6

5 1 6 2 3 5 2 4 1 5

Make a table and enter the data using tally marks. Find the number that appeared.

(a) The minimum number of times

(b) The maximum number of times

(c) Find those numbers that appear an equal number of times.

Solution

Constructing a table using tally marks we have

a) From the table, the number 4 has appeared only 4 times, and hence is the number that appeared minimum number of times.

b) The maximum number of times a number has appeared is 11. Hence 5 appeared the maximum number of times.

c) 1 and 6 have appeared equal number of times, that is, 7 times.

4. Following pictograph shows the number of tractors in five villages.

Observe the pictograph and answer the following questions.

(i) Which village has the minimum number of tractors?

(ii) Which village has the maximum number of tractors?

(iii) How many more tractors village C has as compared to village B.

(iv) What is the total number of tractors in all the five villages?

Solution

a) There are 3 tractor pictures for Village D which is less than the number of tractors for all the other villages. So, Village D has the minimum number of tractors.

b) There are 8 tractor pictures for Village C which is more than the number of tractors for all the other villages. So, Village C has the maximum number of tractors.

c) Village B has 5 tractors and village C has 8 tractors. So, there are 8 – 5 = 3 tractors more in village C than in village B.

d) There are 28 tractor pictures in all, which shows the total number of tractors in all the five villages.

5. The number of girl students in each class of a co-educational middle school is depicted by the pictograph:

Observe this pictograph and answer the following questions:

(a) Which class has the minimum number of girl students?

(b) Is the number of girls in Class VI less than the number of girls in Class V?

(c) How many girls are there in Class VII?

Solution

a) There are lesser number of pictures in class VIII when compared to all other classes. So, class VIII 

has the minimum number of girl students.

b) We see that there are 4 pictures for class VI. As we see that, 

from the pictograph, there are 4 × 4 = 16 girls in class VI. There are 2 pictures representing 8 girls 

and a half picture representing 2 girls. So, there are 10 girls in class V.

Class VI has 16 – 10 = 6 girls more than class V.

c) There are 3 pictures representing 3 × 4 = 12 students in class VII.

6. The sale of electric bulbs on different days of a week is shown below:

What can we conclude from the said pictograph?

Solution

a) Each picture of a bulb represents 2 bulbs according to the pictograph. So, 12 bulbs were sold on Monday, 16 bulbs were sold on Tuesday, 8 bulbs on Wednesday, 10 bulbs on Thursday, 14 bulbs on Friday, 8 bulbs on Saturday and 18 bulbs on Sunday.

b) Maximum number of bulbs were sold on Sunday.

c) Same number of bulbs were sold on Wednesday and Saturday and it is the minimum number of bulbs.

d) Total bulbs sold in a week is 12 + 16 + 8 + 10 + 14 + 8 + 18 = 86 bulbs.

7. In a village six fruit merchants sold the following number of fruit baskets in a particular season

Observe this pictograph and answer the following questions:

(a) Which merchant sold the maximum number of baskets?

(b) How many fruit baskets were sold by Anwar?

(c) The merchants who have sold 600 or more number of baskets are planning to buy a godown for the next season. Can you name them?

Solution

a) Each basket in the pictograph represents 100 baskets. There are more number of basket pictures for Martin, which shows that he sold the maximum number.

b) There are 7 basket images for Anwar in the graph. So, he sold 700 baskets.

c) Anwar has sold 700 baskets, Martin sold 900 + 50 = 950 baskets and Ranjit Singh sold 800 baskets. So, Anwar, Martin and Ranjit Singh sold more than 600 baskets. Therefore, they are planning to buy a godown.

Exercise 9.2

1. Total number of animals in five villages are as follows:

Village A : 80

Village B : 120

Village C : 90

Village D : 40

Village E : 60

Prepare a pictograph of these animals using one symbol  to represent 10 animals and answer the following questions:

(a) How many symbols represent animals of village E?

(b) Which village has the maximum number of animals?

(c) Which village has more animals: village A or village C?

Solution

The pictograph using the symbol = 10 animals is as follows:

a) 6 symbols represent animals of village E.

b) From the pictograph, we see that there is more number of symbols for Village B and hence it has the maximum number of animals.

c) There are 8 symbols in village A which shows that there are 80 animals in village A and there are 9 symbols in village B, which shows that there are 90 animals in village C. So, village C has more number of animals than village A.

2. Total number of students of a school in different years is shown in the following table

             

A. Prepare a pictograph of students using one symbol to represent 100 students and answer the following questions:

(a) How many symbols represent total number of students in the year 2002?

(b) How many symbols represent total number of students for the year 1998?

B. Prepare another pictograph of students using any other symbol each representing 50 students. Which pictograph do you find more informative?

Solution

The pictograph looks as follows:

a) 6

b) 5 complete symbols and 1 incomplete symbol.

c) The pictograph looks as follows:

This pictograph is more informative.

Exercise 9.3

1. The bar graph given below shows the amount of wheat purchased by government during the year 1998-2002. Read the bar graph and write down your observations.

In which year was

(a) the wheat production maximum?

(b) the wheat production minimum?

Solution

a) The maximum wheat production is shown by the longest bar, which is for the year 2002.

b) The minimum wheat production is shown by the smallest bar and is for the year 1998.

2. Observe this bar graph which is showing the sale of shirts in a ready-made shop from Monday to Saturday.

Now answer the following questions:

(a) What information does the above bar graph give?

(b) What is the scale chosen on the horizontal line representing number of shirts?

(c) On which day was the maximum number of shirts sold? How many shirts were sold on that day?

(d) On which day was the minimum number of shirts sold?

(e) How many shirts were sold on Thursday?

Solution

a) The bar graph represents the number of shirts sold from Monday to Saturday.

b) 1 unit = 5 shirts

c) The maximum number of shirts sold on a particular day is represented by the longest bar, which is on Saturday. From the graph, we see that 60 shirts were sold on Saturday.

d) The minimum number of shirts sold on a particular day is represented by the shortest bar, which is on Tuesday.

e) 35 shirts were sold on Thursday.

3. Observe this bar graph which shows the marks obtained by Aziz in half-yearly examination in different subjects. Answer the given questions.

(a) What information does the bar graph give?

(b) Name the subject in which Aziz scored maximum marks.

(c) Name the subject in which he has scored minimum marks.

(d) State the name of the subjects and marks obtained in each of them.

Solution

a) The graph shows the marks obtained by Aziz in various subjects.

b) Aziz scored maximum marks in Hindi as it is represented by the longest bar in the graph.

c) He scored minimum marks in Social studies, which is represented by the smallest bar in the graph.

d)         Hindi – 80 marks

English – 60 marks

Mathematics – 70 marks

Science – 50 marks

           Social studies – 40 marks

Exercise 9.4

1. A survey of 120 school students was done to find which activity they prefer to do in their free time.

 

Draw a bar graph to illustrate the above data taking scale of 1 unit length = 5 students.

Which activity is preferred by most of the students other than playing?

Solution

Taking scale 1 unit length = 5 students, the bar graph looks as below:

 Other than playing, the activity that is preferred most is Reading story books.

2. The number of Mathematics books sold by a shopkeeper on six consecutive days is shown below:

 

Draw a bar graph to represent the above information choosing the scale of your choice.

Solution

The bar graph with scale 1 unit length = 5 books is as shown below.

3. Following table shows the number of bicycles manufactured in a factory during the years 1998 to 2002. Illustrate this data using a bar graph. Choose a scale of your choice.

 

(a) In which year was the maximum number of bicycles manufactured?

(b) In which year was the minimum number of bicycles manufactured?

Solution

The graph below shows the number of bicycles manufactured in a factory during 1998 to 2002.

a) Maximum number of bicycles was manufactured in the year 2002.

b) Minimum number of bicycles was manufactured in the year 1999.

4. Number of persons in various age groups in a town is given in the following table.

Draw a bar graph to represent the above information and answer the following questions. (take 1 unit length = 20 thousands)

(a) Which two age groups have same population?

(b) All persons in the age group of 60 and above are called senior citizens. How many senior citizens are there in the town?

Solution

The bar graph is as shown below:

 a) Age groups 30 – 44 and 45 – 59

b) All persons in the age group of 60 and above are called senior citizens. There are 80,000 people in the age group 60 – 74 and 40,000 in the age group 75 and above. So totally, there are 80,000 + 40,000 = 1,20,000 senior citizens in the town.

CLASS 6 CHAPTER 8: DECIMALS

Exercise 8.1

1.      Write the following as numbers in the given table:

Solution

One block divided into 10 equal parts means each part is 1/10 (one-tenth) of a unit. It can be written as 0.1 in decimal notation. One block divided into 100 equal parts means each part is (1/100) one-hundredth of a unit.

a)      We see that there are three towers made of 10 blocks representing 3 tens, one block representing ones and two parts of a block representing 2 tenths.

This can be shown on the table as:

Hundreds	Tens	Ones	Tenths
0	3	1	2

b)      In this we see 1 hundreds, 1 tens and 4 tenths.

Hundreds	Tens	Ones	Tenths
1	1	0	4

2.      Write the following decimals in the place value table.

(a)    19.4 (b) 0.3 (c) 10.6 (d) 205.9

Solution

	Hundreds	Tens	Ones	Tenths
a)	0	1	9	4
b)	0	0	0	3
c)	0	1	0	6
d)	2	0	5	9

3.      Write each of the following as decimals:

(a) Seven-tenths (b) Two tens and nine-tenths (c) Fourteen point six (d) One hundred and   two ones (e) Six hundred point eight

Solution

a)      Seven-tenths = 

  

b)      Two tens and nine tenths = 

c)      Fourteen point six = 14.6

d)     One hundred and two ones = 100 + 2 = 102

e)      Six hundred point eight = 600.8

4.      Write each of the following as decimals:

Solution

a)      There are 5 tenths in the number. So, the decimal representation is 0.5

b)      There are 3 ones and 7 tenths in the number. So, the decimal representation is 3.7

c)      There are 2 hundreds, 6 tens, 5 ones and 1 tenth in the number. So, the decimal representation is 265.1

d)     There are 7 tens, 0 ones and 8 tenths in the number. So, the decimal representation is 70.8

e)       

f)  

      

g)      For writing in decimal notation, the denominator of the fraction should be 10. So, we make an equivalent fraction as,

Now, writing this fraction in decimal form,

h)     

 

i)

         

j)         

k)       

5.      Write the following decimals as fractions. Reduce the fractions to lowest form.

(a)    0.6 (b) 2.5 (c) 1.0 (d) 3.8 (e) 13.7 (f) 21.2 (g) 6.4

Solution

6.      Express the following as cm using decimals.

(a)    2 mm (b) 30 mm (c) 116 mm (d) 4 cm 2 mm (e) 162 mm (f) 83 mm

Solution

We know that 10 mm is 1 cm.

            

7.      Between which two whole numbers on the number line are the given numbers lie? Which of these whole numbers is nearer the number?

a)      0.8 b) 5.1   c) 2.6   d) 6.4   e) 9.1   f) 4.9

Solution

a)      0.8 = 0 + 8/10

So, it lies between 0 and 1 and is nearer to 1.

b)      5.1 = 5 + 1/10

So, it lies between 5 and 6 and is nearer to 5.

c)      2.6 = 2 + 6/10

So, it lies between 2 and 3 and is nearer to 3.

d)     6.4 = 6 + 4/10

So, it lies between 6 and 7 and is nearer to 6.

e)      9.1 = 9 + 1/10

So, it lies between 9 and 10 and is nearer to 9.

f)       4.9 = 4 + 9/10

So, it lies between 4 and 5 and is nearer to 5.

8.      Show the following numbers on the number line.

(a) 0.2 (b) 1.9 (c) 1.1 (d) 2.5

Solution

a)      0.2 lies between 0 and 1. There are 2 tenths in it. Divide the unit length into 10 equal parts and 0.2 represents the 2^nd part.

b)      1.9 lies between 1 and 2. There are 9 tenths in it. 1.9 represents the ninth part after 1.

c)      1.1 lies between 1 and 2. There are 1 tenths in it. 1.1 represents the first part after 1.

d)     2.5 lies between 2 and 3. There are 5 tenths in it. 2.5 represents the fifth part after 2.

9.      Write the decimal number represented by the points A, B, C, D on the given number line.

Solution

           A represents the 8^th equal part between 0 and 1. So, A is 0.8.

B represents the 3^rd equal part between 1 and 2. So, B is 1.3, C represents the 2^nd equal part between 2 and 3 and hence is the number 2.2 and D is 2.9, the 9^th equal part between 2 and 3.

10.  (a) The length of Ramesh’s notebook is 9 cm 5 mm. What will be its length in cm?

(b)   The length of a young gram plant is 65 mm. Express its length in cm.

Solution

a)      The length of Ramesh’s notebook is 9 cm 5 mm.

b)      The length of a young gram plant is 65 mm.

Exercise 8.2

1)      Complete the table with the help of these boxes and use decimals to write the number.

Solution

a)      There are two tenths and 6 hundredths. So, the decimal is 0.26

b)      One whole or ones, 3 tenths and 8 hundredths. Decimal is 1.38

c)      One whole or ones, two tenths and 8 hundredths. Decimal is 1.28

	Ones	Tenths	Hundredths	Number
(a)	0	2	6	0.26
(b)	1	3	8	1.38
(c)	1	2	8	1.28

2)      Write the numbers given in the following place value table in decimal form.

Solution

3)      Write the following decimals in the place value table.

(a) 0.29 (b) 2.08 (c) 19.60 (d) 148.32 (e) 200.812

Solution

Let us write the decimals in expanded form.

Now, let us complete the table.

	Hundreds	Tens	Ones	Tenths	Hundredths	Thousandths
a)	0	0	0	2	0	0
b)	0	0	2	0	8	0
c)	0	1	9	6	0	0
d)	1	4	8	3	2	0
e)	2	0	0	8	1	2

           

4)      Write each of the following as decimals.

Solution

5)      Write each of the following decimals in words.

(a) 0.03 (b) 1.20 (c) 108.56 (d) 10.07 (e) 0.032 (f) 5.008

Solution

a)      0.03 = zero point zero three

b)      1.20 = one point two zero

c)      108.56 = one hundred eight point five six.

d)     10.07 = ten point zero seven.

e)      0.032 = zero point zero three two

f)       5.008 = five point zero zero eight

6)      Between which two numbers in tenths place on the number line does each of the given number lie?

(a)    0.06 (b) 0.45 (c) 0.19 (d) 0.66 (e) 0.92 (f) 0.57

Solution

1.      0.06 lies between 0 and 0.1

2.      0.45 lies between 0.4 and 0.5

3.      0.19 lies between 0.1 and 0.2

4.      0.66 lies between 0.6 and 0.7

5.      0.92 lies between 0.9 and 1

6.      0.57 lies between 0.5 and 0.6

7)      Write as fractions in lowest terms.

(a)    0.60 (b) 0.05 (c) 0.75 (d) 0.18 (e) 0.25 (f) 0.125  (g) 0.066

Solution

Exercise 8.3

1)      Which is greater?

a)      0.3 or 0.4

b)      0.07 or 0.02

c)      3 or 0.8

d)     0.5 or 0.05

e)      1.23 or 1.2

f)       0.099 or 0.19

g)      1.5 or 1.50

h)      1.431 or 1.490

i)        3.3 or 3.300

j)        5.64 or 5.603

Solution

a)      0.3 = 3/10 and 0.4 = 4/10

The whole number part is the same. It can be seen that the tenth part (3) of 0.3 is less than the tenth part (4) of 0.4.

So, 0.4 is greater.

b)      0.07 = 7/100 and 0.02 = 2/100

The whole number part is the same. It can be seen that the hundredth part (7) of 0.07 is greater than the hundredth part (2) of 0.02.

So, 0.07 is greater.

c)      3 or 0.8

0.8 = 8/100

The whole part 3 is greater than the decimal 0.8

So, 3 is greater

d)     0.5 or 0.05

0.5 = 5/10 and 0.05 = 5/100

The whole part is the same. Tenth part of 0.5 is 5 and the tenth part of 0.05 is 0. So, we see that the tenth part of 0.5 is greater than the tenth part of 0.05. So, 0.5 is greater.

e)      1.23 or 1.2

Whole part is 1 and is the same. The tenth part is also the same. The hundredth part of 1.23 is 3 and the hundredth part of 1.2 is 0. So, we see that 1.23 I greater.

f)       0.099 or 0.19

Whole number part is the same. The tenth part of 0.099 is 0 and that of 0.19 is 1. So, the tenth part of 0.19 is greater than 0.099. Hence, 0.19 is greater.

g)      1.5 or 1.50

Whole number is the same. The tenth part is the same. So, the numbers are equal.

h)      1.431 or 1.490

The whole number is the same. The number in the tenth part is also the same. The hundredth part of 1.431 is 3 and that of 1.491 is 9. We see that 3 < 9 and hence 1.431 is lesser than 1.490.

Hence, 1.490 is greater.

i)        3.3 or 3.300

The whole number part and the tenth part are the same. When there are no digits in the hundredths and the thousandths place of the number, we know that the digits are zero.

So, the numbers are the same.

j)        5.64 or 5.603

The whole number and the tenth place digits are the same. As 4 is greater than 0, we know that 5.64 is greater than 5.603.

So, 5.64 is greater.

EXERCISE 8.4

1.      Express as rupees using decimals.

a)      5 paise

b)      75 paise

c)      20 paise 

d)     50 rupees 90 paise

e)      725 paise

Solution

We know that 100 paise = Re 1

Therefore, 1 paise = Re 1/100 = Re 0.01

          

2.      Express as metres using decimals.

a)15 cm (b) 6 cm (c) 2 m 45 cm d) 9 m 7 cm (e) 419 cm

Solution

1 cm = 1/100 m or 0.01 m

 

  

3.      Express as cm using decimals.

a) 5 mm (b) 60 mm (c) 164 mm d) 9 cm 8 mm (e) 93 mm

Solution

We know that

1 cm = 1/10 mm or 0.1 mm.

  

4.      Express as km using decimals.

a)      8 m (b) 88 m (c) 8888 m d) 70 km 5 m

Solution

1 m = 1/1000 km or 0.001 km

5.      Express as kg using decimals.

a)      2 g (b) 100 g (c) 3750 g d) 5 kg 8 g (e) 26 kg 50 g

Solution

1 g = 1/1000 kg = 0.001 kg

EXERCISE 8.5

1. Find the sum in each of the following:

(a) 0.007 + 8.5 + 30.08

(b) 15 + 0.632 + 13.8

(c) 27.076 + 0.55 + 0.004

(d) 25.65 + 9.005 + 3.7

(e) 0.75 + 10.425 + 2

(f) 280.69 + 25.2 + 38

Solution

a)      0.007 + 8.5 + 30.08

  

b)      15 + 0.632 + 13.8

c)      27.076 + 0.55 + 0.004

d)     25.65 + 9.005 + 3.7

 

e)      0.75 + 10.425 + 2

 

f)       280.69 + 25.2 + 38

 

2. Rashid spent Rs 35.75 for Maths book and Rs 32.60 for Science book. Find the total

amount spent by Rashid.

Solution

Amount spent for Maths book = Rs. 35.75

Amount spent for Science book = Rs. 32.60

Total amount spent for the books = 35.75 + 32.60

 

  

So, Rashid spent Rs. 68.35 for the books.

3. Radhika’s mother gave her Rs 10.50 and her father gave her Rs 15.80, find the total

amount given to Radhika by the parents.

Solution

Amount given by mother = Rs. 10.50

Amount given by father = Rs. 15.80

Total amount = Rs. 10.50 + 15.80

 

The total amount given to Radhika by her parents is Rs. 26.30

4. Nasreen bought 3 m 20 cm cloth for her shirt and 2 m 5 cm cloth for her trouser. Find

the total length of cloth bought by her.

Solution

Length of the cloth purchased for shirt = 3 m 20 cm 

=

Length of the cloth purchased for trouser = 2 m 5 cm

=

Total length of the cloth purchased =

 

Total length of the cloth purchased = 5.25 m

5. Naresh walked 2 km 35 m in the morning and 1 km 7 m in the evening. How much distance did he walk in all?

Solution

Distance walked in the morning = 2 km 35 m

Distance covered in the evening = 1 km 7 m

 Distance he walked in all =

Distance Naresh walked in all = 3.042 km

6. Sunita travelled 15 km 268 m by bus, 7 km 7 m by car and 500 m on foot in order to

reach her school. How far is her school from her residence?

Solution

Distance travelled by bus = 15 km 268 m

Distance travelled by car = 7 km 7 m

Distance travelled on foot = 500 m = 0.5 km

Total distance travelled =

 

Total distance travelled is 22.775 km

7. Ravi purchased 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850g flour. Find the total

weight of his purchases.

Solution

Amount of rice = 5 kg 400 g = 5.400 kg

Amount of sugar = 2 kg 20 g = 2.020 kg

Amount of flour = 10 kg 850 g = 10.850 kg

Total purchase =

Total amount of purchase = 18.270 kg

EXERCISE 8.6

1.      Subtract :

a)      Rs 18.25 from Rs 20.75

b)      202.54 m from 250 m

c)      Rs 5.36 from Rs 8.40

d)     2.051 km from 5.206 km

e)      0.314 kg from 2.107 kg

Solution

a)      Rs 18.25 from Rs 20.75

b)      202.54 m from 250 m

 

c)      Rs 5.36 from Rs 8.40

 

d)     2.051 km from 5.206 km

 

e)      0.314 kg from 2.107 kg

 

2.      Find the value of :

a)      9.756 – 6.28

b)      21.05 – 15.27

c)      18.5 – 6.79

d)     11.6 – 9.847

Solution

a)      9.756 – 6.28

b)      21.05 – 15.27

c)      18.5 – 6.79

 

d)     11.6 – 9.847

3.      Raju bought a book for Rs 35.65. He gave Rs 50 to the shopkeeper. How much money did he get back from the shopkeeper?

Solution

Cost of the book Raju purchased = Rs. 35.65

Money paid by Raju to the shopkeeper = Rs. 50

Remaining = Rs. 50 – Rs. 35.65

Hence, Raju gets back Rs. 14.35

4.      Rani had Rs 18.50. She bought one ice-cream for Rs 11.75. How much money does she have now?

Solution

Money with Rani = Rs. 18.50

Amount she spent on an ice-cream = Rs. 11.75

Remaining = 18.50 – 11.75

Now Rani has Rs. 6.75 left with her.

5.      Tina had 20 m 5 cm long cloth. She cuts 4 m 50 cm length of cloth from this for making a curtain. How much cloth is left with her?

Solution

Length of the cloth Tina had = 20 m 5 cm = 20.05 m

Length of the cloth she cuts = 4 m 50 cm = 4.50 m

Length of the cloth left with her = 20.05 m – 4.50 m

So, 15.55 m cloth was left with her.

6.      Namita travels 20 km 50 m every day. Out of this she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto?

Solution

Total distance Namita travelled every day is 20 km 50 m = 20.050 km

Distance travelled in bus is 10 km 200 m = 10.200 km

Distance travelled in auto =

 

She travelled 9.850 km by auto.

7.      Aakash bought vegetables weighing 10 kg. Out of this, 3 kg 500 g is onions, 2 kg 75 g is tomatoes and the rest is potatoes. What is the weight of the potatoes?

Solution

Total weight of the vegetables purchased = 10 kg

Weight of onions = 3 kg 500 g = 3.500 kg

Weight of tomatoes = 2 kg 75 g = 2.075 kg

Weight of onions and tomatoes = 3.500 + 2.075

Weight of potatoes = Weight of the vegetables – weight of onions and tomatoes

                               =  10 – 5.575

 

Weight of potatoes is 4.425 kg.